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MappingAce

[Swift JSON to Struct, class] MappingAce allows rapid creation of swift struct , Swift class, OC class . Automatic transform dictionary to model(model could be struct), forget to manually write property mapping code

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MappingAce

Swift Swift

CocoaPods Compatible Carthage Compatible License

Swift JSON to Struct, class

MappingAce allows rapid creation of struct , Swift class, OC class . Automatic transform dictionary to model(model could be struct), forget to manually write property mapping code

Usage

JSON -> Model

Raw struct

// It is recommend to implement protocol `Mapping`, and just implement `Mapping`, no more works
struct PhoneNumber: Mapping{
    var tel: String
    var type: String
}

let phoneInfo: [String : Any] = [
    "tel": "186xxxxxxxx",
    "type": "work"
]
let phone = PhoneNumber(fromDic: phoneInfo)

print(phone.tel) //"186xxxxxxxx"
print(phone.type) //"work"



// Struct did not implement the `Mapping` protocol
struct PhoneNumber {
    var tel: String
    var type: String
}

let phone = MappingAny(type: PhoneEntity.self, fromDic: phoneInfo)
    
Nested struct mapping
struct User{
    var age: Int
    var name: String
    var phone: PhoneNumber
}

// if you want your serilized nested struct, just implement the `Mapping` protocol
struct PhoneNumber: Mapping {
    var tel: String
    var type: String
}

let dic: [String : Any] = [
    "age" : 24,
    "name": "Binglin",
    "phone": phoneInfo
]

let user = MappingAny(type: User.self, fromDic: dic)
Optional property
struct User{
    var age: Int?
    var name: String?
    var phone: PhoneNumber?
}

private struct PhoneNumber: Mapping {
    var tel: String
    var type: String
}

let dic: [String : Any] = [
    "name": "Binglin",
]

let user = MappingAny(type: User.self, fromDic: dic)

XCTAssertEqual(user.age, nil)
XCTAssertEqual(user.name, "Binglin")
XCTAssertEqual(user.phone?.tel, nil)
XCTAssertEqual(user.phone?.type, nil)
Enum

enum type of Int & String is support

// eg: EnumInt
enum Gender: Int, EnumInt{
    case male = 1
    case female = 2
}

struct User: Mapping{
    var gender: Gender
}

let dicGender: [String : Any] = ["gender": 1]
let userMale = User(fromDic: dicGender)

XCTAssertEqual(userMale.gender, Gender.male)
// when enum is string type
enum Gender: String, EnumString{
    case male = "m"
    case female = "f"
}

Struct or class has default property value

protocol: InitMapping (Struct or Class)

// struct
struct User: InitMapping{
    var name: String = "default"
    var age: Int?
}

let dic: [String : Any] = ["age": 14]
let user = User(fromDic: dic)

print(user.name) //"default"
print(user.age)  //14


// class
// need to implement an empty initializer.
class User: NSObject, InitMapping{
    var name: String = "default"
    var age: Int?

    required override init() {}/*required*/
}

let dic: [String : Any] = ["name" : "IB"]
let user = User(fromDic: dic)

Model -> JSON

// for object implement Mapping or InitMapping
struct PhoneNumber: Mapping {
    var tel: String
    var type: String
}

let phone = PhoneNumber(tel: "186xxxxxxxx", type: "work")
let toDic = phone.toDictionary()
print(toDic) // ["type": "work", "tel": "186xxxxxxxx"]


// for object do not implement Mapping or InitMapping
// just implement protocol Serializable
struct PhoneNumber: `Serializable` {
    var tel: String
    var type: String
}

let phone = PhoneNumber(tel: "186xxxxxxxx", type: "work")
let toDic = phone.toDictionary()
print(toDic) // ["type": "work", "tel": "186xxxxxxxx"]

Installation

swift versionframework version
3.01.0.2
3.11.0.3
4.01.0.4

Installation with CocoaPods

Podfile

To integrate MappingAce into your Xcode project using CocoaPods, specify it in your Podfile:

platform :ios, '8.0'

target 'TargetName' do
pod 'MappingAce', '~> 1.0.3'
end

Then, run the following command:

$ pod install

Installation with Carthage

To integrate MappingAce into your Xcode project using Carthage, specify it in your Cartfile:

github "IcyButterfly/MappingAce" ~> 1.0.3

Run carthage to build the framework and drag the built MappingAce.framework into your Xcode project.

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